Several things swirled in my mind the last couple of days
culminating in the question. Does learning chemistry impose an additional
cognitive load on students, perhaps even more so than the other sciences? Is
there something unique about introductory
level chemistry that requires special attention from us teachers in designing
our learning activities?
I meet new people on occasion, and this past week, finding
out that I teach chemistry led to a personal disclosure from my new
acquaintance about how chemistry was hard and didn’t make sense in school. I
don’t hear this as much about biology or physics, but that might just be a
sampling effect due to my being a chemist. I’ve also been reading Reactions by Peter Atkins. It is
beautifully illustrated with chemical substances at the molecular level on
virtually every page. I did not find the prose as engaging, and I don’t
personally recommend it if I wanted to get you excited about chemistry; Periodic Tales is much better.
But one thing that Reactions does
well is showing you lots of molecular level pictures. This “molecular view” is
something my colleagues and I stress heavily in our introductory chemistry
classes.
Why is the molecular view so important for chemists? That’s
where all the action is! Chemistry is about making and breaking chemical bonds,
a chaotic dance where atomic partners are swapped. But the problem is that we
cannot see this frenetic molecular
level activity with our own eyes. We see macroscopic changes such as bubbles, a
color change, perhaps a spark of light, or glimpse the appearance or
disappearance of a solid. As I’ve been thinking about cognitive load and
the differences between how experts and novices learn and process new
information, it’s perhaps worth taking a step back to see how one might view a
chemical reaction.
Consider the hydration of formaldehyde to form methylene
glycol. This is a reaction of interest to chemical engineers, atmospheric
chemists, and those who study the chemistry of the origin-of-life such as
myself. If I asked a student to write a chemical equation for this reaction, I
might get CH2O + H2O -->
CH4O2 from a student in an introductory chemistry class
who knew the “chemical formulae” of each of these substances. A student in
organic chemistry might write the product methylene glycol as CH2(OH)2
to represent something about how the atoms are connected in the molecule.
Thinking molecularly, one might imagine the reaction to look
like:
A student in organic chemistry might “draw” the reaction as:
The carbonyl (C=O) bond of formaldehyde is emphasized since
a key chemical reaction of carbonyls is to undergo “nucleophilic addition”.
Methylene glycol is drawn as a “line structure” where carbons are not
explicitly labeled and hydrogens attached to carbons are not shown.
A student thinking about how the reaction proceeds would
consider what chemical bonds are broken in the reactants, and what bonds are
being made when the product is formed. A simple representational drawing of the
“transition state” as the midpoint within the chemical reaction is shown below.
Dashed lines represent the bonds being “made and broken”. Also notice the C–H
bonds that do not participate in the chemical reaction are drawn with wedges
that show how the CH2O and H2O molecules approach each
other in three-dimensional space for a productive reaction.
How does this reaction happen in practice? If you were an
atmospheric chemist, volatile formaldehyde could dissolve in cloud droplets.
You might therefore write the reaction as: CH2O(g) + H2O(l) --> CH2(OH)2(aq)
with the phases of matter of each substance specified (g = gas, l = liquid, aq
= aqueous, a solution of a substance dissolved in water). If you were measuring
this reaction in a lab, it would never involve just two molecules colliding to
form a new molecule. The formaldehyde molecule as it dissolves into water would
encounter many water molecules. In fact there is likely to exist a different
transition state where the presence of other water molecules assists (or
catalyzes) the chemical reaction. Below is a different transition state that is
much more likely to occur than the one previously shown because it is energetically more feasible. (Energy is
the currency in chemical reactions!)
In fact, there are other transition states more complex than
the one above that may be even more probable. (I know this because all my new
research students from the last five years do a series of computations on this
very reaction as their first test case.) Formaldehyde dissolving in water,
viewed at the molecular level, is likely to look like just a lot of water! The
water molecules are closely spaced as shown in the water “box” below. (Such
boxes are a standard part of the simulator’s toolkit.) You’d be hard-pressed to
find a formaldehyde molecule even in a relatively concentrated solution, such
as a 1 M (or one molar) solution. In a 1 M solution, one mole of formaldehyde
is dissolved in 1 L of water. That’s approximately 2 molecules of formaldehyde
per 111 molecules of water.
When we teach students to write “balanced” chemical
equations, and then calculate the amount of product formed given some amount of
starting reactants, the chemical reactions are written in terms of the mole
(6.022 x 1023 molecules). So while on the one hand we want students
to think of “balanced” chemical reactions at the molecular level (with
molecular pictures in mind), we also want them to be able to think of these
same reaction at the level of moles, or the macroscopic level. One mole of
water, at18 mL in volume (or just over a tablespoon) is an amount you can
physically observe.
As a chemistry professor (or the “expert”), shifting back
and forth between the molecular level and the macroscopic level, not to mention
thinking about all the different representations shown above, poses practically
no cognitive load. All these ways of thinking about the reaction have become
second nature, and my mind effortlessly moves to the representation I need for
the problem at hand. But this is not true of the student (or the “novice”). The
cognitive load can be substantial. One reason why the introductory college
chemistry course is particularly challenging is that students enter college
with highly varied backgrounds. The student who has taken Advanced Placement
Chemistry is much more comfortable “shifting gears” than the students who has
taken no chemistry, or barely understood any of it.
When I first conceived of a Potions for Muggles textbook, I
thought it should be heavily illustrated with molecular pictures (like most
popular chemistry textbooks today) because that’s how I think about chemistry
as the expert. But I’m starting to see that an over-emphasis of the simple (and
pretty) molecular pictures sometimes obscures understanding instead of illuminating
it simply by imposing an additional cognitive load that a reader may not be
ready for. The transition from novice to expert requires quickly identifying
the key elements of a problem. Novices are awash in a sea of information and
it’s hard to prioritize which representational view is going to help them
tackle the issue at hand. I still think pictures are important but they should
be chosen with care.
The formaldehyde hydration reaction is actually a bit more
complicated because (1) it can go in reverse, and (2) formaldehyde can react
with methylene glycol to form the C2H6O3
molecule (HO-CH2-O-CH2-OH), depending on the relative
amounts of formaldehyde and water. If one simply considered one molecule of
formaldehyde and one molecule of water in a highly artificial system, then (1)
is easy to deal with, and (2) is irrelevant. But in a real system involving
moles of molecules, things could get much more complicated. For example, a
third molecule of formaldehyde could add to the C2H6O3
molecule, eliminate a water
molecule in the process, and form the trioxane shown below.
Great insights on cognitive load in learning chemistry! At USCA Academy, we prioritize effective teaching strategies to help students manage complexity. Thanks for sharing these valuable tips!
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