After considering
two simpler situations, we are now ready to tackle a more difficult problem.
How would the strength of covalent bonds change if we magically resized matter?
We care about this because living creatures are predominantly made up of
molecules containing covalent bonds. So if you were engorging a spider to scare
Ron Weasley, or you have obtained the technology of Ant-Man’s suit, you might
care to know the side-effects – which may turn out not to be secondary but
instead devastatingly problematic.
The challenge here
is that the covalent bond is not as easy to describe because it is inherently
quantum mechanical. Back in Part 1, we used a simple model to describe ionic
bonds relying on the classical Coulomb’s Law, which works satisfactorily for
the most part. Then in Part 2, we discussed weak attractive inter-particle
forces using an intuitive (also classical) polarizability model. There
is no classical analog to describe covalent bonding, and the intuitive model
found in many general chemistry textbooks is misleading. Here’s one from a
former textbook I’ve used before.
I show students
this figure because it is familiar to them if they have taken chemistry in high
school. The main idea: By conveniently locating the negatively charged
electrons between the positively charged nuclei, this shared pair
of electrons attracts both atomic centers and thereby holds the molecule
together. A wave of the hand then concludes that this attractive force
outweighs the repulsive forces. The figure implies these repulsive forces are
electrostatic, and while that might be true for H2, it’s certainly
not true for anything larger when Pauli repulsion kicks in. I tell the students
that the figure is partly true but partly misleading.
Why is it partly
true: The potential energy term due to electrostatic attraction between the
electrons and the nuclei does give rise to the attractive force in the covalent
bond. And it is sufficiently strong to outweigh the repulsive forces at the
appropriate equilibrium bond distance. Why it is misleading: A chemical bond is
defined with reference to the infinitely separated atoms. As the atoms approach
each other to form a bond, the energy-stabilizing contribution due to the
potential energy is actually reduced. Egad! Shouldn’t that cause the bond not
to form? It turns out that the repulsive contribution of the kinetic energy is
reduced even more. Hence, there is a net stabilization of energy due to forming
the covalent bond. (Quantum Mechanics folks: We’ve assumed that the covalent
bond is represented by the Heitler-London wavefunction.)
All this is a bit
too complicated for the general chemistry student, and so in recent years I’ve
moved away from this approach of introducing the topic of chemical bonding. My most recent approach is to use the General Bond Energy Curve early on, and briefly discuss different attractive and repulsive contributions. Then we
get into the details of ionic bonds, covalent bonds, and intermolecular forces.
The equilibrium distances and equilibrium bond energies change but the overall
curve still has a steep repulsive part on the left, an optimum well in the
middle, and a shallower attractive part on the right that asymptotically
approaches zero energy – the reference state for infinitely separated
particles, be they atoms, ions or molecules.
Now back to
resizing matter. How would the strength of the covalent bond change if atoms
magically or technologically changed in size? Using the same assumptions laid
out in Part 2, we would expect that the outermost electrons are held more
weakly by the nucleus and therefore the energy-stabilizing attractive
contribution due to potential energy should be weakened. We see this if we
compared the covalent bonds of the Cl2 versus I2
molecules. The larger iodine atoms lead to a longer and weaker I–I bond
compared to the smaller chlorine atoms which have a shorter and stronger Cl–Cl
bond. Br2 lies in between, as befits the intermediate atomic size of
bromine. (F2 is anomalous because of the Pauli Principle!)
How would the
kinetic energy change? That’s a bit more difficult to picture. The simple
notion of using 0.5 mv2 likely fails us here. That’s because
to some extent the electrons are “localized” in the mid-point region, but in a
different sense the kinetic energy drops because they have more “space” to move
around in per the overlap of the two orbitals that contribute to the bond.
Technically the decrease in kinetic energy can be approximated by the square of
the gradient of the molecule’s wavefunction compared to the separated atoms.
Does the decrease in kinetic energy decrease proportionally to the decrease in
potential energy?
Honestly, I’m not
sure what the answer should be. (Sorry to disappoint you!) If there is a
relationship between the two, it’s likely not to be linear. To solve this
problem, I would actually need to do is set up a quantum mechanical calculation
involving two “mutant” atoms with approximate properties I would expect for a
magically resized atom. The answers from this calculation would still be
approximate, but I would have a better idea how both equilibrium bond energies
change as a function of the resized atoms. I’m too lazy to do the calculation
at the moment so I will make a guess. (I imagine this is how my students feel
sometimes when they encounter my exam questions.) I will guess that bigger
atoms lead to longer bonds with weaker attractive potential energy, and
although the repulsive kinetic energy term is also lower in magnitude, the fact
that a chemical bond exists suggests that the potential energy term is overall
larger in magnitude than the kinetic energy term, and therefore more impacted
as the equilibrium bond distances change.
While I’m dissatisfied
with my answer, and assuming I’m in the Advanced Arithmancy course, I
submit it to the Hogwarts professor grading my exam. Hopefully it will be
graded soon and an answer key provided. That way I don’t have to actually do
the hard work and be willing to accept a not-so-good grade. I suppose sometimes
school is about trade-offs, and I’m reminded in a tiny way what it’s like to be
in the shoes of my students.
No comments:
Post a Comment